limx的x次方等于1
x的ⅹ次方极限为1是因为:
lim(x→0)x^x=e^lim(Ⅹ→0)lnx^x
=e^lim(x→0)xlnx
=e^lim(x→0)lnx/1/x
=e^lim(ⅹ→0)1/x/(-1/x²)
=e^lim(ⅹ→0)(-x)=e^0=1
limx的x次方等于1
x的ⅹ次方极限为1是因为:
lim(x→0)x^x=e^lim(Ⅹ→0)lnx^x
=e^lim(x→0)xlnx
=e^lim(x→0)lnx/1/x
=e^lim(ⅹ→0)1/x/(-1/x²)
=e^lim(ⅹ→0)(-x)=e^0=1