把这几个数都转换成相同的进制数,然后才好比较大小。
(110110101)B = (1,1011,0101)B = (01B5)H
(316)Q = (011,001,110)B = (0,1100,1110)B = (00CE)H
(259)D = (256+3)D = (0103)H
那么,都转换成了 十六进制,比较结果如下:
(01B5)H > (01A5)H > (0103)H > (00CE)H
由此可知,(110110101)B 是最大的数
1a5h等于多少d
题目为二进制向十进制转换,计算过程如下 8+4+2+1+0.5+0.25=15.75 即 (1111.11)B=(15.75)D